Error Counting Number Of Fingers In Eclipse

[Geeve]

Hi Everyone ,

I'm working on a project to count the number of fingers that I show above my leap motion.
I'm a Java Developer and use eclipse for this purpose.
The problem is that , If I show 2 fingers ( or anything else ) I always get that it detects 5 Fingers ( always )
If I show 2 fingers each in both hands , I always get back that 10 fingers are detected.
I hope you guys can help me sort this problem , thanks alot in advance

My OnFrame code is :

public void onFrame(Controller controller) {

		Frame frame = controller.frame();

		Hand hand = new Hand();

		System.out.println("Frame id: " + frame.id()
				+ ", Timestamp: " + frame.timestamp()
				+ ", Hands:" + frame.hands().count()
				+ ", Fingers:" + frame.fingers().count()
				+ ", Tools" + frame.tools().count()
				+ ", Gestures" + frame.gestures().count());

	}
			        }

This is how Log looks like :

Frame id: 18176, Timestamp: 11929113372, Hands:2, Fingers:10, Tools0, Gestures0
Frame id: 18177, Timestamp: 11929148336, Hands:2, Fingers:10, Tools0, Gestures0
Frame id: 18178, Timestamp: 11929174006, Hands:1, Fingers:5, Tools0, Gestures0
Frame id: 18179, Timestamp: 11929174456, Hands:1, Fingers:5, Tools0, Gestures0
(I deleted the Log in between because they are the same )
Frame id: 18192, Timestamp: 11929333259, Hands:0, Fingers:0, Tools0, Gestures0

[RuZman]

Since 2.x the skeletal tracking model reports five fingers for each hand:

For example, if you count visible fingers or otherwise distinguish
between fingers extended outward and those retracted toward the hand,
you will have to use the new |Pointable_isExtended|_
finger properties to know which fingers are extended or not. If, on the
other hand, you relied on fingers disappearing when they touched each
other, then you will have to establish a minimum distance threshold
between the finger tips instead, since the fingers will no longer
disappear.
https://developer.leapmotion.com/documentation/java/devguide/Intro_Skeleton_API.html .

Use frame.fingers().extended().count() instead of frame.fingers().count()

[Geeve]

Thanks alot @RuZman
It resolved the problem , I went through the data.
But , I have another problem that persists , that is : I wrote a code to detect if I opened three fingers in my left hand or three fingers in my right hand , but the log always says that I opened three fingers in my Right hand ever though I open it in my left hand.

This is the code I wrote :

	public void onFrame(Controller controller) {
		
		Frame frame = controller.frame();
		
		Hand hand = new Hand();
		
		if((hand.isRight()&&(frame.fingers().extended().count()==3))){
			System.out.println("RIGHT HAND THREE FINGERS OPEN!");
		}
		else if((hand.isLeft()&&(frame.fingers().extended().count()==3))){
			System.out.println("LEFT HAND THREE FINGERS OPEN!");
		}
		
		
		
			
	}

But the log always shows RIGHT HAND.
Hope you can help me out , thanks again

[RuZman]

Hand hand = new Hand(); will not be useful. You can not create a "real world" hand. You have to ask the Leap Motion whether there is a hand in the "real world".

    Frame frame = controller.frame();
    if(frame.hands().count() > 0) {
        Hand hand = frame.hands().get(0);
        
        // your code            
    }

This will code will only work with one hand inside the interaction box of the leap motion controller. To use 2 hands you could do something like:

    if(frame.hands().count() > 0) {
        Hand leftmostHand = frame.hands().leftmost();
        
        if(leftmostHand.isLeft() && leftmostHand.fingers().extended().count()==3) {
            
        }
        
        Hand rightmostHand = frame.hands().rightmost();
        
        if(rightmostHand.isRight() && rightmostHand.fingers().extended().count()==3) {
            
        }
    }

(Code is not testetd, hope it works.)

[Geeve]

Thanks alot your idea works really well!
I figured out another way to do it using for
I wanted to know how can i identify middle , index or ring finger that i show above leap motion and print "YOU OPENED INDEX FINGER" . Thank you.
Hope you can help me , thanks for all the help till now!

public void onFrame(Controller controller) {		
 			
Frame frame = controller.frame();
			
for(Hand hand : frame.hands()) {
	String handType = hand.isLeft() ? "Left Hand" : "Right Hand";
				
		if((handType=="Left Hand")&&(frame.fingers().extended().count()==3))
			{
			System.out.println("THREE FINGERS OPEN LEFT HAND");
			}
	else if((handType=="Right Hand")&&(frame.fingers().extended().count()==3))
			{
			System.out.println("THREE FINGERS OPEN RIGHT HAND");
			}
					else
					; //null statement
			
				
			}

[RuZman]

First of all, you shouldn't compare two Strings in Java with '=='. Use equals() instead. Your solution is good, because it might work with multiple hands. There is just one little bug. Use the variable 'hand' of your iterator. 'frame.fingers()' will return all fingers which the leap motion detects (of each hand).

for(Hand hand : frame.hands()) {
    String handType = ? "Left Hand" : "Right Hand";
			
    if(hand.isLeft() && (hand.fingers().extended().count()==3))
    {
        System.out.println("THREE FINGERS OPEN LEFT HAND");
    }
    else if(hand.isRight() && (hand.fingers().extended().count()==3))
    {
        System.out.println("THREE FINGERS OPEN RIGHT HAND");
    }
}

Use identify the middle, index or ring finger use the method fingerType:

FingerList indexFingerList = hand.fingers().fingerType(Finger.Type.TYPE_INDEX);
Finger indexFinger = indexFingerList.get(0); //since there is only one per hand
JavaDoc

Use a boolean flag to save the previous status of each finger and print your message if something changes.

private boolean isIndexFingerExtended = false;

public void doSomething() {
    if(!isIndexFingerExtended && indexFinger.isExtended()) {
        System.out.println("index -> opened");
        isIndexFingerExtended = true;
    } else if(isIndexFingerExtended && !indexFinger.isExtended()) {
        System.out.println("index -> closed");
        isIndexFingerExtended = false;
    }
}

[hassanwaqas1998]

I am facing the same problem but with python 2.7.x How would I approach to resolve this in python. I want the leap motion to detect and give an output of a correct number of fingers being displayed instead of 5 all the time.
edit: using python 2.7 with pycharm

def on_frame(self, controller):
    data = []
    print "on frame========"
    # Get the most recent frame and report some basic information
    frame = controller.frame()

    print "Frame id: %d, timestamp: %d, hands: %d, fingers: %d, tools: %d, gestures: %d" % (
          frame.id, frame.timestamp, len(frame.hands), len(frame.fingers), len(frame.tools), len(frame.gestures()))
    data.append(frame.id if frame.id else '')
    data.append(frame.timestamp if frame.timestamp else '')
    # data.append(len(frame.hands))
    data.append(len(frame.fingers) if frame.fingers else 0)
    # data.append(len(frame.tools))
    data.append(len(frame.gestures()))

and

        # Get fingers
        for finger in hand.fingers:
            print "    %s finger, id: %d, length: %fmm, width: %fmm" % (
                self.finger_names[finger.type],
                finger.id,
                finger.length,
                finger.width)

            data.append(finger.id if finger.id else '')
            data.append(finger.length if finger.length else 0)
            data.append(finger.width if finger.width else 0)

            # Get bones
            for b in range(0, 4):
                bone = finger.bone(b)
                print "      Bone: %s, start: %s, end: %s, direction: %s" % (
                    self.bone_names[bone.type],
                    bone.prev_joint,
                    bone.next_joint,
                    bone.direction)
                data.append(self.bone_names[bone.type] if self.bone_names[bone.type] else '')
                data.append(bone.prev_joint if bone.prev_joint else '')
                data.append(bone.next_joint if bone.next_joint else '')
                data.append(bone.direction if bone.direction else '')

if my provided info is not not sufficient, then let me know and I will provide more.

Thank you

[rogerjordan1980]

I'll be sure to keep an eye on this thread. Thanks for sharing. Bumped into your thread.