C# Find angle between hand and finger (Bending) Leap Team Help

[unalmusasadik]

Hello i tried a lot of ways to find bending in finger can you help me I tried these ways:

First Way:

  double angle = (180 - ( hand.Direction.AngleTo(finger.Direction) / Math.PI) * 180);

Second Way:

 double angle = Math.Abs(((hand.Direction.z - finger.Direction.z) / Math.PI) * 180) * 2;

Thanks Musa

[PLeoncini]

The first one seems fine. Are you sure finger points to a valid finger?

[unalmusasadik]

The first one seems fine. Are you sure finger points to a valid finger?

Thanks for your answer my code:

foreach (Finger finger in frame.Fingers)
{

     Bone bone1 = finger.Bone(Bone.BoneType.TYPE_PROXIMAL);
     Bone bone2 = finger.Bone(Bone.BoneType.TYPE_INTERMEDIATE); 

     double angle = (180 - ( hand.Direction.AngleTo(finger.Direction) / Math.PI) * 180);

[unalmusasadik]

And also it's continue like thar =>

if (finger.Type == Finger.FingerType.TYPE_INDEX)
                {
                    fingeri.Invoke((MethodInvoker)(() => fingeri.Text = "Index: " + angle.ToString()));
                } 

else if (finger.Type == Finger.FingerType.TYPE_THUMB)
                {
                    fingert.Invoke((MethodInvoker)(() => fingert.Text = "Thumb: " + angle.ToString()));
                }

All finger reads done like that in the code

[unalmusasadik]

guys can you help (leap team)